思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
Compatible with Android apps
The 36-year-old, a two-time European Tour winner, was scheduled to be playing in this week’s South African Open Championship at Stellenbosch Golf Club but was forced to withdraw after the incident on Wednesday.，详情可参考新收录的资料
Варвара Кошечкина (редактор отдела оперативной информации)
，详情可参考新收录的资料
這對伊朗而言等同投降。放棄導彈與盟友，甚至可能在領導層看來，比起攻擊威脅更容易導致政權更迭。
Node **buckets = (Node**)calloc(bucketCount, sizeof(Node*));。新收录的资料是该领域的重要参考